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8t^2-7t-100=0
a = 8; b = -7; c = -100;
Δ = b2-4ac
Δ = -72-4·8·(-100)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-57}{2*8}=\frac{-50}{16} =-3+1/8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+57}{2*8}=\frac{64}{16} =4 $
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